# Calculate minimum and maximum Ethernet (IEEE 802.3) frame size from frame format

According the frame format of Ethernet

Minimum Frame Size should be :

7Bytes + 1Bytes + 6Bytes + 6Bytes + 2Bytes + 46Bytes +4Bytes = 72Bytes


Maximum Frame Size should be :

 7Bytes + 1Bytes + 6Bytes+ 6Bytes + 2Bytes + 1500Bytes + 4Bytes = 1526Bytes


But it is said that the minimum frame size is $$64Bytes$$ while the maximum frame size is $$1518 Bytes$$.

How the frame sizes are calculated ?