# Cryptography: Play Fair cipher

In our university, we were taught that since all 26 letters cant be placed together in a $$5*5$$ square matrix we must put $$i/j$$ together like this represented in the below diagram. Here our key is $$monarchy$$, now what would have happened if the key contained $$j$$ in itself? say if the key would have been $$jargon$$ then how do we accommodate the one extra letter which should have been left?

• Are questions like this considered on-topic? Oct 22, 2019 at 19:57