4
$\begingroup$

Suppose I have an undirected graph with four vertices $a,b,c,d$ which are connected as in a simple path from $a$ to $d$, i.e. the edge set $\{(a,b), (b,c), (c,d)\}$. Then I have seen the following proposed as a greedy algorithm to find a maximal matching here (page 2, middle of the page)

Maximal Matching (G, V, E):
M = []
While (no more edges can be added)
     Select an edge which does not have any vertex in common with edges in M
     M.append(e)
end while
return M

It seems that this algorithm is entirely dependent on the order chosen for which edge is chosen first. For instance in my example if you choose edge $(b,c)$ first, then the you will have a matching that consists only of $(b,c)$.

Whereas if you choose $(a,b)$ as your starting edge, then the next edge chosen will be $(c,d)$ and you have a matching of cardinality 2.

Am I missing something, as this seems wrong? I have also seen this described as an algorithm for finding a maximal matching in the context of proving that the vertex cover approximation algorithm selects a vertex cover by choosing edges according to a maximal matching. Any insights appreciated.

$\endgroup$

1 Answer 1

13
$\begingroup$

You're correct, you're not missing anything -- except that the algorithm is not wrong. The task is to choose a maximal matching, not a maximum matching. There may be many possible maximal matchings, many of which are not maximum matchings. It's the difference between a local optimum vs a global optimum.

$\endgroup$
1
  • $\begingroup$ @einpoklum-reinstateMonica, oh, so it is. Thanks. Edited. $\endgroup$
    – D.W.
    Nov 5, 2019 at 21:46

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.