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I have been told that inorder tree tranversal of binary search trees returns the tree elements in order. I came up with this binary search tree:

      20
    /
 10
    \
     26

However the inorder tree tranversal of this seems to be 10, 26, 20?! What is wrong here?

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  • $\begingroup$ "I have been told that inorder tree tranversal", it should have been binary search tree. $\endgroup$
    – Turing101
    Dec 17, 2019 at 13:46
  • $\begingroup$ @HIRAKMONDAL yes I meant to say that $\endgroup$
    – CcVHKakalLLOOPPOkKkkKk
    Dec 17, 2019 at 15:48
  • $\begingroup$ In your "ASCII-art", is the root at the left or at the top? $\endgroup$
    – greybeard
    Dec 17, 2019 at 17:07
  • $\begingroup$ (Could you decide on traversal rather than transversal?) $\endgroup$
    – greybeard
    Dec 17, 2019 at 17:10

2 Answers 2

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This is not a valid binary search tree, since 26 is greater than 20 and is in its left subtree.

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That is not correct BST as Narek mentioned. BST should be - 

 20
/   \
10  26

For inorder traversal, start visiting tree from Top to bottom and left to right manner and print a node only when it is referenced 2nd time.

So, inorder traversal here would be 10,20,26.

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