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Is it true that the heaviest edge in a directed graph can not be in the MST of that graph?

I don't think it is true because we might end up with a heaviest edge that is not part of a cycle.

Can anyone confirm?

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    $\begingroup$ Let $G$ be a graph with a bridge. $\endgroup$ – Pål GD May 9 '13 at 15:24
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No, it is not true. Consider a graph with 2 vertices and an edge between them. This is the heaviest edge, and it will be in the minimum spanning tree of $G$.

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    $\begingroup$ And this is not degenerate example, a leaf node with the heaviest edge... $\endgroup$ – Aryabhata May 9 '13 at 4:03
  • $\begingroup$ Yeah, consider any pendant vertex. $\endgroup$ – Juho May 9 '13 at 4:05
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    $\begingroup$ Or any edge in a tree. $\endgroup$ – Luke Mathieson May 9 '13 at 4:06
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    $\begingroup$ More precisely: the heaviest edge is not chosen iff it is on a cycle. $\endgroup$ – Hendrik Jan May 9 '13 at 7:33
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    $\begingroup$ Every bridge is in every MST. $\endgroup$ – Pål GD May 9 '13 at 15:23

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