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Like the title says. I can't figure out how to prove this.

I think it probably has to do with the polynomial hierarchy collapsing but I'm not sure.

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$P \subseteq RP $, $BPP \subseteq PSPACE $.

So $PSPACE \subseteq P $, $-->$ $BPP \subseteq RP $.

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    $\begingroup$ Thank you for your answer! $\endgroup$ – Pedro Costa Jun 16 '20 at 15:51

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