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I have an idea of how to approach the problem, but I'm not sure about it. Given a Turing Machine, I can check how many states the machine has, and somehow by the number of states to know if the run uses endless cells of the tape. However, I am not sure how I can use the number of states and what I should check. What confuses me is that entering an endless loop does not necessarily require the use of endless cells of the film.

$L_k=\{<M>| \,M\,\,\,is\,\,a\,\,TM\,\,that\,\,uses\,\,at\,\,most\,\,k\,\,tape\,\,cells\,\,\,when\,\,\,running\,\,\,on\,\,\,\epsilon\}$

prove that: $L^*=\bigcup\limits_{k\,\in\,\mathbb{N}} L_k\,\in\,\,\,RE\setminus R$

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  • $\begingroup$ Is $k$ an absolute constant or is $L = \{ M : \exists k, M(\epsilon) \text{ uses at most $k$ tape cells} \}$? Do you just need to prove that there is a TM that accepts $L$? Or you want to decide $L$? $\endgroup$
    – Steven
    Jun 19 '20 at 1:15
  • $\begingroup$ I updated what I wrote, I hope it's clear now $\endgroup$
    – Ella
    Jun 19 '20 at 5:02
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The language $L^*$ consists of all Turing machines $M$ which either eventually halt or repeat a configuration. For each machine $M$, by simulating the machine you can easily observe that one of these possibilities has happened.

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  • $\begingroup$ using infinite number of tape cells not considered an endless loop? $\endgroup$
    – Ella
    Jun 19 '20 at 7:35
  • $\begingroup$ Thanks, changed to "repeat a configuration". $\endgroup$ Jun 19 '20 at 7:38
  • $\begingroup$ Is it always true that once a configuration is repeated, the Turing machine necessarily uses a finite number of cells? $\endgroup$
    – Ella
    Jun 19 '20 at 7:42
  • $\begingroup$ Yes. I'll let you figure out why. $\endgroup$ Jun 19 '20 at 7:43

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