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Let $G = (V, E)$ be an undirected graph and $U \subseteq V$ some subset of its vertices. An induced graph $G[U]$ is graph created from $G$ by removing all vertices that are not part of the set $U$.

I want to find a polynomial time algorithm that has graph $G = (V, E)$ and integer $k$ as input and returns a maximum set $U \subseteq V$ with largest size such that all vertices of $G[U]$ have degree at most $k$.

My idea with greedy algorithm that removes vertices with largest degree or vertices connected with most vertices with degree greater than $k$ doesn't work.

Does anyone know how to solve this problem in polynomial time?

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  • $\begingroup$ @PålGD I edited question, is it comprehensible for you now? $\endgroup$ – jason Jul 1 '20 at 10:30
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Let $G$ be any graph and let $k = 0$.

This problem is, as you correctly pointed out in a comment, better known as Independent Set and is famously NP-complete.

It is therefore unlikely that there is an algorithm solving your problem (which is slightly more general) in polynomial time.

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  • $\begingroup$ k and G is an input you cannot let it be whatever you want. Also i don't see how this would answer the question. $\endgroup$ – jason Jul 1 '20 at 12:22
  • $\begingroup$ Return largest possible subset of V such that for every (v1, v2) in that subset {v1, v2} is not an element of E. In other words largest set of vertices not connected by edge $\endgroup$ – jason Jul 1 '20 at 14:05
  • $\begingroup$ Ok I think I know what you ment by that. It leaves us with NP complete problem: en.wikipedia.org/wiki/Independent_set_(graph_theory) Thank you for help. $\endgroup$ – jason Jul 1 '20 at 14:27

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