I am currently studying for my exam and I am having trouble to solve this question:
Right or wrong: If $A$ is context-free then $A^*$ is regular.
I think it's wrong because if $A$ is context-free it means that $A$ can be a non-regular language. And the non-regular languages are not closed under the Kleene star operation (at least I think so). I am not sure how write this in a more formal way.
Maybe like this?
Let $A=\{a^nb^n \mid n \in \mathbb{N}\}$. Then we know that $A$ is non-regular and context-free. However, I'm not sure what $A^*$ is.