Does SQL need subqueries?

Imagine a sufficiently generalized implementation of the structured query language for relation databases. Since the structure of the canonical SQL SELECT statement is actually pretty important for this to make sense, I don't appeal directly to relational algebra, but you could frame this in those terms by making appropriate restrictions on the form of expressions.

An SQL SELECT query generally consists of a projection (the SELECT part) some number of JOIN operations (the JOIN part), some number of SELECTION operations (in SQL, the WHERE clauses), and then set-wise operations (UNION, EXCEPT, INTERSECT, etc.), followed by another SQL SELECT query.

Tables being joined can be the computed results of expressions; in other words, we can have a statement such as:

SELECT t1.name, t2.address
  FROM table1 AS t1 
  JOIN (SELECT id, address 
          FROM table2 AS t3 
         WHERE t3.id = t1.id) AS t2
 WHERE t1.salary > 50,000;

We will refer to the use of a computed table as part of an SQL query as a subquery. In the example above, the second (indented) SELECT is a subquery.

Can all SQL queries be written in such a way as to not use subqueries? The example above can:

SELECT t1.name, t2.address
  FROM table1 AS t1 
  JOIN table2 AS t2
    ON t1.id = t2.id
 WHERE t1.salary > 50,000;

This example is somewhat spurious, or trivial, but one can imagine instances where considerably more effort might be required to recover an equivalent expression. In other words, is it the case that for every SQL query $q$ with subqueries, there exists a query $q'$ without subqueries such that $q$ and $q'$ are guaranteed to produce the same results for the same underlying tables? Let us limit SQL queries to the following form:

SELECT <attribute>,
 FROM <a table, not a subquery>
 JOIN <a table, not a subquery>
 JOIN <a table, not a subquery>
WHERE <condition>
  AND <condition>
  AND <condition>



And so on. I think left and right outer joins don't add much, but if I am mistaken, please feel free to point that out... in any event, they are fair game as well. As far as set operations go, I guess any of them are fine... union, difference, symmetric difference, intersection, etc... anything that is helpful. Are there any known forms to which all SQL queries can be reduced? Do any of these eliminate subqueries? Or are there some instances where no equivalent, subquery-free query exists? References are appreciated... or a demonstration (by proof) that they are or aren't required would be fantastic. Thanks, and sorry if this is a celebrated (or trivial) result of which I am painfully ignorant.

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    $\begingroup$ My gut tells me that you can always join together everything and select from there as long as you do not need aggregated values. Selecting all entries with a value larger than the average of its column seems to require computing the averge first, therefore needing a subquery. $\endgroup$ – Raphael Mar 8 '12 at 6:08
  • $\begingroup$ @Raphael I'm fairly certain you can even do aggregated values, you just need to do more self-joins and group-bys (making it exponentially larger, but still possible). Not sure how I'd formally prove you can do everything that way, though. $\endgroup$ – Kevin Mar 8 '12 at 16:10
  • $\begingroup$ @Kevin Are you sure the number of operations needed does not depend on the number of rows? Because we can't have that, can we? $\endgroup$ – Raphael Mar 8 '12 at 18:33
  • 1
    $\begingroup$ The normal example I have for requiring a subquery is counting duplicates: select count(*) from (select id from sometable group by id having count(*)>1) d. Because it includes group by I have not put this as an answer. $\endgroup$ – Mark Hurd Mar 21 '12 at 14:44
  • $\begingroup$ BTW AFAIK in normal SQL the ON clause is required for JOINs, though a cross product is obtained with just a comma. $\endgroup$ – Mark Hurd Mar 21 '12 at 14:51

There is some terminology confusion; the query block within parenthesis

SELECT t1.name, t2.address
  FROM table1 
  JOIN (SELECT id, address 
          FROM table2 AS t3 
         WHERE t3.id = t1.id) 

is called inner view. A subquery is query block within either WHERE or SELECT clause, e.g.

select deptno from dept
where 3 < (select count(1) from emp 
           where dept.deptno=emp.deptno)

In either case, inner view or subquery can be unnested into "flat" project-restrict-join. Correlated subquery with aggregation unnests into inner views with grouping, which then unnests into flat query.

select deptno from dept d
    where 3 < (select avg(sal) from emp e
               where d.deptno=e.deptno)

select d.deptno from dept d, ( 
    select deptno from emp e
    group by deptno
    having avg(sal) > 3
) where d.deptno=e.deptno

select d.deptno from dept d, emp e
where d.deptno=e.deptno 
group by d.deptno
having avg(sal) > 3

As for algebraic rules for query optimization, relational algebra is known to be axiomatized into Relational Lattice which simplifies query transformations as demonstrated here and there.

  • $\begingroup$ I am curious. Can you add an example of a query that uses some fields average, e.g. selecting all entries with above-average value? It is not clear to me how that would look like after flattening. $\endgroup$ – Raphael Jun 8 '12 at 12:15

To translate your statement into the relational algebra, I think it asks:

Can we rewrite $\sigma_A(A)\bowtie \sigma_B(B)$ as $\sigma_A(\sigma_B(A\bowtie B))$?

(Where $\sigma$ is select and $\bowtie$ is join.)

The answer is "Yes," and it's a standard query optimization. To be honest, I'm not sure how to prove this in a non-question-begging manner - it's just a property of selection and join. You can argue inductively to add however many layers of nested queries you want.

Additionally, you might ask:

Can every sequence of joins be written as $A\bowtie B\bowtie C\bowtie\dots$ [As opposed to, say, $(A\bowtie B)\bowtie(C\bowtie D)$]?

Again the answer is yes, because join is associative. Similar statements can be made about projection as well.

One notable type of "subquery" which I think cannot be "flattened out" is with. One way to see this is to note that if you have a with statement then you can have a recursive function, which cannot be written without using subqueries.

So to sum up: in the specific case you mentioned, no, SQL does not need subqueries, and you can prove it inductively. In general though, there are features which require subqueries.

  • $\begingroup$ Recursive behaviour via with was introduced in SQL:1999, and makes the resulting language strictly more expressive. $\endgroup$ – András Salamon Apr 27 '13 at 15:28

"Do subqueries add expressive power to SQL queries?"

They did, at least before the introduction of EXCEPT in the SQL language.

Prior to the introduction of EXCEPT, there was no way what so ever to express a relational difference or semidifference in SQL without resorting to subqueries.

These days, all of the "typical" primitive operators of "the" relational algebra can be expressed without subqueries :

NATURAL JOIN can be done through NATURAL JOIN, or JOIN ON
UNION can be done through UNION
MINUS can be done through EXCEPT
RESTRICT can be done through WHERE
relational literals can be done through VALUES
transitive closures can be done through recursive WITH


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