0
$\begingroup$

Consider $x$ = $(0.1001)_b$ and $F$[3,2]. ($F$[3,2] is the set of all floating point numbers with 3 digits in the mantissa and 2 digits in the exponent.)

The question is $x$ in the working range [3,2]?

I am quite confused does $F$[3,2] mean $(0.111)_b$ x $2^{11}$ = $(111)_b$?

$\endgroup$
1
  • 1
    $\begingroup$ It depends how you are representing the numbers. In normal form $x$ is represented as $1.001e{-1}$. You don't need to store the $1$ on the left. So, you have space for the three digits $001$ and the exponent $-1$. $\endgroup$ – plop Aug 10 '20 at 13:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.