I'm struggle on this practice question from this site....
Calculate the number of bits required in the address for memory having size of 16 GB. Assume the memory is 4-byte addressable.
MY QUESTION IS: what is the difference between an "address" and "the memory is 4 byte addressable"?
I understand an address would be its location in memory that is represented by bits, such as 2^n, where n is the number of bits in the address. But I'm confused about addressable in this question and how that's different than address
2^n * 4 bytes = 2^34 The solution is 32 bits