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What is the VC Dimension of the class of $k$-dimensional cross-polytope (1-norm ($l_1$) balls)?

A $k$-dimensional $l_1$ ball with radius $r\in \mathcal R$ and center $\mathbb v\in \mathcal R^k$ is

$\{\mathbb x\in\mathcal R^k: ||\mathbb x-\mathbb v||_1\le r\}$.

Namely, denote $\mathbb x = [x_1,x_2,...,x_k]$ and $\mathbb v = [v_1,v_2,...,v_k]$, A $k$-dimensional $l_1$ ball with radius $r$ and center $\mathbb v$ is

$\{\mathbb x\in\mathcal R^k, |x_1-v_1|+|x_2-v_2|+...+|x_k-v_k|\le r\}$.

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  • $\begingroup$ Can you answer this for $k = 1$? $\endgroup$ Commented Aug 6, 2021 at 22:14
  • $\begingroup$ When $k=1$, the class of 1-norm balls becomes the class of intervals whose VC Dimension is 2. $\endgroup$ Commented Aug 7, 2021 at 6:20
  • $\begingroup$ Does the answer change for larger $k$? $\endgroup$ Commented Aug 7, 2021 at 13:12
  • $\begingroup$ Yes. When $k=2$, the class of $l_1$ balls is the class of squares whose edges parallel the $[1,1]$ or $[1,-1]$. The VC Dimension of such class of squares is 3. $\endgroup$ Commented Aug 7, 2021 at 13:28
  • $\begingroup$ What happens for $k=3$? $\endgroup$ Commented Aug 7, 2021 at 13:30

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