# Can possiblity of hash collision be "zero" when we hash same file in different formats?

Let's say I have a file A, which is any normal file (pdf, jpeg, mp3 etc.)
Now I get the binary dump of file, say another file B{A}.
And the hexdump of file say, file H{A}.
Now I hash all the three files with any 256 bit HASH (SHA256, BLAKE256 etc.)
I want to know that :
1. What is the possiblity of hash collision in this case (Considering if somehow I find a collison in case of file A, I still can generate the hex and binary dump of that file to see if hashes of B{A} and H{A} matches or not).
2. Will it still be 1/256* 256* 256? Or
3. Will there be 0 collision ? (Considering collision between exactly same size of files)

Approximating a Hash function $$h$$ as a function that maps each word in $$\{0,1\}^*$$ to a word in $$\{0,1\}^{256}$$ chosen uniformly at random, you can find the probability that at least one of the events:
• $$h(A)=h(B\{A\})$$,
• $$h(A)=h(H\{A\})$$,
• $$h(B\{A\})=h(H\{A\})$$
is true by looking at the complementary probability. The probability that $$h(A)$$, $$h(B\{A\})$$, and $$h(H\{A\})$$ are all distinct is $$1 \cdot (1 - \frac{1}{2^{256}}) \cdot (1 - \frac{2}{2^{256}})$$. Then, the probability of having at least one collision is then: $$1- \left(1 - \frac{1}{2^{256}}\right) \cdot \left(1 - \frac{2}{2^{256}}\right) \approx 2.6 \cdot 10^{-77}.$$