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We need to find mth smallest possible distance by considering all possible pairs. I solved this problem by considering all possible pairs and maintaining a max priority queue. If the max priority queue size is less than m I push the current distance into it. Otherwise, if the size of the priority queue is greater than equal to m I check whether top of priority queue is greater than it. If so, I pop it and push this distance. The time complexity of this solution seems to be O(N^2 logn) while space complexity O(m). Can we do better than this? Especially can we do this in O(1) extra space.

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    $\begingroup$ It doesn't really matter for this question, but this "distance" is not a mathematical distance metric $\endgroup$
    – nir shahar
    Oct 9 at 15:58
  • $\begingroup$ The title you have chosen is not well suited to representing your question. Please take some time to improve it; we have collected some advice here. Thank you! $\endgroup$
    – D.W.
    Oct 10 at 6:42
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There is a $O(n \log n)$ solution by divide and conquer, see for example here for Euclidean distances (shouldn't make much of a difference for this problem).

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  • $\begingroup$ thanks a lot. It is helpful $\endgroup$ Oct 11 at 11:52

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