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Question: Consider an arbitrary directed graph $G$ with weighted vertices, the weights can be positive, negative or $0$. The prefix of $G$ is a subset of vertices $P$ such that there's no edge $(u \rightarrow v)$ if $v \in P$ and $u \not\in P$. Find an integer linear programming to describe the maximum weight prefix of G.

I'm new to linear programming and struggling in come up a LP solution.

The objective function seems trivial, we let $x_v$ be a variable to indicate whether that vertex in or not in the prefix. Thus we have, $$\sum_{v \in V} w(v)x_v$$

However, I'm not sure how to impose the prefix constraint such that if we pick a vertex $v$, we must have to pick its prefix vertex say $u$, if there's a directed edge from $u$ to $v$. So it seems like we have to check all edges, for each directed edge $(u \rightarrow v)$, if $v \in P$ then $u \in P$. I can only describe this verbally, any suggestion is highly appreciated.

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  • $\begingroup$ It seems that you are looking for an integer linear program. $\endgroup$
    – Steven
    Nov 18 at 19:31
  • $\begingroup$ That's right, sorry I forgot to mention this. $\endgroup$
    – hh vh
    Nov 18 at 19:32
  • $\begingroup$ Please edit the question to correct the problem statement based on the feedback you have received. Don't just append "Edit: some more stuff". Instead, revise it so it reads well for someone who encounters it for the first time. See cs.meta.stackexchange.com/q/657/755 $\endgroup$
    – D.W.
    Nov 19 at 23:34
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To encode the fact that if $(u,v)$ is an edge then you you cannot have $u \not\in P$ and $v \in P$ you can add (for each edge) the following constraint:

$$ (1-x_u) + x_v \le 1, $$

equivalently: $$ x_v - x_u \le 0. $$

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