0
$\begingroup$

For example, is $(X \vee 1)$ a valid formula in conjunctive normal form (CNF)?

If yes, then I would have to consider such formulas when trying to prove a statement about all CNF formulas.

$\endgroup$
1
  • $\begingroup$ This could depend on your definition of CNF. $\endgroup$ Mar 6, 2022 at 9:34

1 Answer 1

1
$\begingroup$

$X \vee 1$ is not a CNF formula because $1$ is neither a variable nor the negation of a variable. Both $X$ and $\neg X$ are valid CNF formulas, however.

$\endgroup$
1
  • $\begingroup$ The question is not hurting anyone. $\endgroup$
    – Pseudonym
    Mar 6, 2022 at 22:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.