What are the six mistakes that were made in the configuration of the following network?
I could only find 3. Since the subnet on the left has 192.168.10.33 as HostMin and 192.168.10.38 as HostMax, Host A4 and Host A5 cannot be in this subnet. Subnet A should also have the IP 2188.8.131.52 because it's a network address.
I can't seem to be able to find the other 3, what am I missing?
On a quick overview, I can find the following problems:
The IP address 192.168.10.32 for interface eth1 of the router is the network address for Subnet A 192.168.10.32/29. While this generally works, there are some really ancient RFCs that prohibit the use of network addresses for hosts. Typically, the address of a router is either the first or the last host address in a network, in this case either 192.168.10.33 or 192.168.10.38.
The same applies to the IP address 192.168.12.0 for interface eth2 of the router, which is the network address of Subnet B 192.168.12.0/23. Traditionally, the router address would either be 192.168.12.1 or 192.168.13.254.
The IP address 192.168.13.0 for interface eth0 of the router is within Subnet B 192.168.12.0/23. Presumably, this is supposed to be the upstream interface to the rest of the world and would thus be in some public subnet, a DMZ, a transit subnet, or maybe an RFC 3021 Point-to-Point /31 subnet.
The EUI-48 MAC address of Switch B 00-11-27-82-H3-E6 is not a valid hexadecimal number representation. Hexadecimal number representation only uses the symbols 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, a / A, b / B, c / C, d / D, e / E, and f / F.
The IP address 192.168.10.39 of Host A4 is the broadcast address for Subnet A 192.168.10.32/29. Broadcast addresses must not be used for hosts.
The IP address 192.168.10.40 of Host A5 is outside Subnet A 192.168.10.32/29.