# Amortized analysis definition confusion

• @YvesDaoust if we consider the process of plugging in an element in an array. The amortized time complexity is $\Theta (1)$. At the same time, in Wikipedia it is said, that the amortized time is less then the individual time complexity of an operator. At the same time $\Theta (1)$ is the result of $\Theta (1)=\frac{\Theta (n)}{n}$, and this last eq. to me looks like we are calculating the total amount of time for n operations, divide by the total amount of them, to find the time for a single operation. May 7 at 13:38
• @YvesDaoust But this contradicts what I just said : "the amortized time is less then the time complexity of an individual operator". I am finding that the amortized time complexity of a single operator is $\Theta(1)$ but at the same time the time complexity of a single operator is bigger then that of an amortized time? May 7 at 13:39