Consider this following Lambda expression:

$$\lambda s. (s \text{ } s )$$

This function applies it's arguement to it's arguement. If this is a valid lambda expression, wouldn't it also be allowed in Haskell if it's based on type theory. What is the obstruction preventing us from doing this?

  • 3
    $\begingroup$ That's untyped lambda calculus $\endgroup$ Feb 15 at 14:31


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