I thought to Assume by way of contradiction that L6 satisfies the conditions of the pumping lemma. Let p be the pumping constant. Consider the word w = 0^(P-1)1...
Clearly w ∈ L6. Thus, by the pumping lemma, there exist x, y, z ∈ Σ^*
such that w = xyz, |xy| ≤ p, |y| > 0 where:
x = 0^m,
y =0^(p-1-m)1,z = etc, the part that left of t he word. if we take i = 1000 for example we get that xy^1000z not in L because we get the following expression: 000000(00000...001)^1000...z (not in L6), but the solution that provided to similar question shows this:
where am I wrong in my attitude to the question?