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Construct a context-sensitive grammar that generates L:

L = {a^n b^m c^k|k>n, k>m}

I believe my productions should go along this lines:

S-> ABCC
A-> a|aBC|BC
B-> b|bBC
C-> c|Cc
CB->BC

The idea is to start with 2 c and keep always one more c, and then with C->c|Cc ad as much c as i want. How can my production for C remember the numbers of m and n.

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Hint. Can you figure out a regular grammar such that for any $k, m, n$ with $k > n$ and $k > m$, there is a word in its language with that number of a, b and c (in any order)?

Hint. Did you know that you can sort with a context sensitive grammar? See an example for inspiration.

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Maybe this?

// end of string marker X
S := TX

// sets up the count relationships
T := TT | AC | BC | C

// sets up the order relationships
BA := AB
CA := AC
CB := BC

// convert to terminals from back to front
Aa := aa
Ab := ab
Ac := ac
Bb := bb
Bc := bc
Cc := cc
CX := c
$\endgroup$

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