Given a set $S$ of points $p_1,..,p_2$ give the most efficient algorithm for determining if any 3 points of the set are collinear.

The problem is I started with general definition but I cannot continue to actually solving the problem.

What can we say about collinear points in general, 3 points $a,b,c$ are collinear if the distance $d(a,c) = d(a,b)+d(b,c)$ in the case when $b$ is between $a$ and $c$.

The naive approach has $O(n(n-1)(n-2))=O(n^3)$ time complexity.

How to solve this problem, what should be the next step?


1 Answer 1


One simple way is to fix a point $x$, compute the slope of the line $xy$ and store it in a hash table for every other point $y$. If there is a collision, then we have collinear points involving $x$. This takes $O(n)$ (if we assume hash table operations take $O(1)$). We then do this for every point $x$ in time $O(n^2)$.

Also if you are aware of the point-line duality (please refer to Artium's comment below), this reduces to checking the $n^2$ possible intersections of $n$ lines, but also makes use of hash tables.

Also it is open whether this can be done in sub-quadratic time as this problem is 3-SUM hard, please refer to this answer.

  • $\begingroup$ Here is an explanation of point-line duality. $\endgroup$
    – Artium
    Jun 22, 2012 at 18:22
  • $\begingroup$ Thank you very much for the full answer! Artium, thank you for the duality link. $\endgroup$
    – com
    Jun 24, 2012 at 3:50
  • $\begingroup$ @Artium, here is a working link to the point-line duality. $\endgroup$ Feb 29, 2020 at 18:24

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