I have, lets say, 8 bits mantissa and 4 bit exponent. Then,
-1=1111 1111
there are no 0s so how can I normalise -1 in 2's complement form?
0
$\begingroup$
$\endgroup$
0
$\begingroup$
$\endgroup$
Sorry, I found out the answer myself. It is 1000 000 manitssa and 0000 exponent.
for mantissa, 1.000 0000 = -128 *power(2,-7).
for exponent, 0000 = 0.
So, result= -128 * power(2,-7)
1000 000manitssa and0000exponent. for mantissa,1.000 0000 = -128 *power(2,-7). for exponent,0000 = 0. So,result= -128 * power(2,-7) = -1. $\endgroup$ – Damodar Dahal May 27 '14 at 6:40