# floating point normalised value of -1

I have, lets say, 8 bits mantissa and 4 bit exponent. Then,

-1=1111 1111 there are no 0s so how can I normalise -1 in 2's complement form?

• Sorry, I found out the answer myself. It is 1000 000 manitssa and 0000 exponent. for mantissa, 1.000 0000 = -128 *power(2,-7). for exponent, 0000 = 0. So, result= -128 * power(2,-7) = -1 . – Damodar Dahal May 27 '14 at 6:40
• This might seem a bit strange but can you write that as an answer instead of as a comment? That way, the question won't sit on our "unanswered" list forever. Thanks and welcome to Stack Exchange! – David Richerby May 27 '14 at 7:47

Sorry, I found out the answer myself. It is 1000 000 manitssa and 0000 exponent. for mantissa, 1.000 0000 = -128 *power(2,-7).
for exponent, 0000 = 0. So, result= -128 * power(2,-7)