If L1 ∪ L2 and L1 are regular, is L2 also regular?

This is a problem in a theory of computation book that's stumping me:

Suppose that we know that $L_1 ∪ L_2$ and $L_1$ are regular. Can we conclude that $L_2$ is regular? Explain.

At first, I thought I could build the NFA that is the union of two DFAs, one which accepts $L_1$, and one which we don't know about. Then lambda transition over to the $L_1$ DFA. Then, the union would be regular, but we wouldn't be able to conclude anything about the $L_2$ DFA.

I think my reasoning is poor though. Could someone please point me in the right direction?

Thank you.

• Hint: make $L_1$ big. Hint 2: make $L_1 \subseteq L_2$.
– Raphael
Feb 5 '15 at 16:27
• – Raphael
Feb 5 '15 at 16:30
• You tell me. :)
– Raphael
Feb 5 '15 at 17:36
• possible duplicate of How to prove a language is regular?
– D.W.
Feb 6 '15 at 0:24

No, since $\Sigma^* \cup L$ and $\Sigma^*$ are regular languages, for any $L$ and there are non-regular languages, we cannot conclude anything about $L$.