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There is a theorem that says if a language is regular, its reverse is regular as well. How can I draw a DFA that shows if a language is regular, it's regular as well?

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  • $\begingroup$ I'm assuming by reverse, you mean its complement. Just change every accepting state in a DFA to rejecting, and every rejecting to accepting. $\endgroup$ – Daniil Agashiyev Feb 21 '15 at 17:02
  • $\begingroup$ What do you mean by a DFA which does all the things itself? $\endgroup$ – babou Feb 22 '15 at 10:49
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$L^R$ is the reverse of the language $L$ and for designing $L^R$ you must:

  1. Reverse all edges in the transition diagram.
  2. The accepting state for the LR automaton is the start state for the main automaton.
  3. Create a new start state for the new automaton with epsilon transitions to reach of the accept states for the main automaton.
  4. Convert this NFA back into a DFA.
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To write the reverse of a DFA, Change all the initial states to final and the final ones to initials(for the later, if there are multiple final states, use a new state and use null transitions to each of them). At last... Reverse the edges.

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  • 1
    $\begingroup$ There's a catch to reversing the edges at least mentioned in the accepted answer. Speaking of which: Does your answer add anything to it? $\endgroup$ – greybeard Feb 13 at 21:22

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