Let's say that you have a 6 qubit system and you want to apply a Hadamard gate to qubits 2 and 4.
How would you construct a matrix that did that, while leaving the state of the other qubits alone?
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Imagine that the qubits were $0$ and $1$ (or $1$ and $2$, depending on your numbering scheme). You want to apply the Hadamard gate on the first two coordinates, and nothing – the identity – on the rest. This leads to a block diagonal matrix whose second block is the $4\times 4$ identity.
Now make the necessary arrangements for the qubits you're interesting it.
answered Oct 18 '15 at 19:20
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$\begingroup$ My question is specifically, what are the necessary arrangements when not using neighboring qubits? :p $\endgroup$ – Alan Wolfe Oct 18 '15 at 20:48
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$\begingroup$ You take the tensor product of your gate and the identity on the rest of the bits. I don't know what you mean by arrangement. In terms of matrices, this is just a block diagonal matrices with its rows and columns shuffled. $\endgroup$ – Yuval Filmus Oct 18 '15 at 20:53
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$\begingroup$ It turns out I didn't ask the question I intended to ask, due to incomplete understanding. Sorry about that Yuval and thanks for your answer! $\endgroup$ – Alan Wolfe Oct 21 '15 at 14:59
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$\begingroup$ Yuval, I meant to ask about a multi qubit gate. For instance, let's say you wanted to apply a controlled not to qubits 2 and 4, in a 6 qubit system. I'd like to ask a new question for that, but the title is going to be the same as the title of this question so not sure. Think I ought to delete this one?? $\endgroup$ – Alan Wolfe Oct 28 '15 at 5:08
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1$\begingroup$ I just went ahead and asked a new one, in case you want some more points hehe. cs.stackexchange.com/questions/48834/… $\endgroup$ – Alan Wolfe Oct 29 '15 at 4:05
