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G:
S -> bRS | RcSa | @(epsilon)
R -> acR | b

....

2-LOOKAHEAD(S->@) = {$,a,aa}
2-LOOKAHEAD(R->b) = {b,ba,bb,bc}

I don't understand a result of these rules..

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when I tried to solve 2-LOOKAHEAD(S->bRS), it solve easily.( {ba,bb} ).

but I don't understand why 2-LOOKAHEAD(S->@) results are {$,a,aa} and

2-LOOKAHEAD(R->b) are {b,ba,bb,bc}. Please explain how to get these results.

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