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The author here writes:

Little known fact, the system of measuring length in the US is Turing complete

enter image description here

My question is: Is the system of measuring length in the US Turing complete?

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    $\begingroup$ I think the author means it as a joke. The measurement system, while certainly intricate and needlessly complex, doesn't look like the right kind of object to be Turing-Complete. It's just a weighted complete graph of conversion factors where the weight on $u\overset{w}{\rightarrow}v$ is the conversion factor from $u$ to $v$. As a stronger argument, this system preserves the parity of the input, in a sense: if $u\overset{a}{\rightarrow}v\overset{b}{\rightarrow}w$ then $u\overset{a\cdot b}{\rightarrow}w$ and $w\overset{\frac{1}{ab}}{\rightarrow}u$. Sorry to disappoint. $\endgroup$ May 19, 2016 at 12:32
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    $\begingroup$ We do not have a senes of humor here. $\endgroup$ May 19, 2016 at 12:59
  • $\begingroup$ @AndrejBauer Perhaps we should have a new tag? $\endgroup$ May 19, 2016 at 14:01
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    $\begingroup$ What would it be, joke? In that case I propose we also introduce kitten-photo. $\endgroup$ May 19, 2016 at 14:12
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    $\begingroup$ @AndrejBauer Those would be tag synonyms for the real tags joke-recognition and furry-calculus-visualization respectively. Some more: for programming-related jokes I propose one-liner. For compiler fun questions -- jest-in-time along with jit as a type synonym. For computer architecture topics -- e-quip-ment. And, of course, we should get new badges: Joker(silver) and Wildcard(gold) -- *nix-pun intended. P.S. This question made my day! :) It's a pity it lacks some $\LaTeX$. $\endgroup$ May 19, 2016 at 16:48

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The post you're referring to is a joke: the US (and similar British Imperial) measurement systems are not Turing complete and the claim is an example of hyperbole.

A key feature that's necessary for a system to be Turing complete is that the system must include computations that do not terminate ("infinite loops"). Although it's not clear exactly what computations can be modeled by unit conversions (or what that even means!), any unit conversion within the diagram takes a finite number of steps.

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    $\begingroup$ Wow, it was a real question that got a real answer. $\endgroup$ May 20, 2016 at 8:36

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