# Difference between word logical addressing and byte logical addressing in this exercise?

I´m new here and this is the first question I´m posting (hopefully this is the correct site).

I have the exercise below:
Consider a virtual address space of 10 pages of 1024 words each (1 word = 2 bytes), mapped onto a physical memory of 32 frames. How many bits are needeed for each virtual address?

| 4 bits for page | 10 bits for offset |


But I don´t figure out how do the 4 bits appear. The exercise explains that the logical addressing is word logical addressing (instead of byte logical addressing).