the partition problem (or number partitioning1) is the task of deciding whether a given multiset S of positive integers can be partitioned into two subsets S1 and S2 such that the sum of the numbers in S1 equals the sum of the numbers in S2.

There is a greedy algorithm for this problem:

One approach to the problem, imitating the way children choose teams for a game, is the greedy algorithm, which iterates through the numbers in descending order, assigning each of them to whichever subset has the smaller sum. This approach has a running time of O(n log n). This heuristic works well in practice when the numbers in the set are of about the same size as its cardinality or less, but it is not guaranteed to produce the best possible partition. For example, given the set S = {4, 5, 6, 7, 8} as input, this greedy algorithm would partition S into subsets {4, 5, 8} and {6, 7}; however, S has an exactly balanced partition into subsets {7, 8} and {4, 5, 6}.

But, I don't know how to prove "This heuristic works well in practice when the numbers in the set are of about the same size as its cardinality or less". Can anyone help?

There is nothing to prove about the statement you highlight. It is an empirical statement.

In order to have something to prove, you will need to formulate this claim formally in some way or another. There are many options, including average-case analysis, smoothed analysis, and restricted instances (which is what the statement points at). Until you have done so, it is impossible to prove or refute the statement.

The example given in your source shows that, in fact, the heuristic doesn't always succeed. Perhaps it gives a good approximation in some circumstances. The statement, unfortunately, doesn't hint at a provable claim which has any chance of being true.

  • You can, of course, perform experiments to validate the statement empirically. That is the closest you could get to "proof". – Tom van der Zanden Sep 26 '16 at 18:42

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Not the answer you're looking for? Browse other questions tagged or ask your own question.