I faced this Boolean expression:
It was solved as follows:
$=C'(A+B)+C(A'+B') $ ...by applying absorption laws $(I)$ $=C'A+C'B+CA'+CB'$
$=(C\oplus A)+(C\oplus B)$
However somehow it did not clicked to me to apply absorption laws. So I did following:
Here, I can have $C'A+CA'=C\oplus A$, but I have following doubt:
What Boolean law / identity I can use to reduce $C'A'B+CAB'$ to $C'B+CB'$ (which then can be reduced to $C\oplus B$) ? Is it even possible? or I have to somehow remember to apply absorption law as shown above and their is not other way to arrive at $(C\oplus A)+(C\oplus B)$ by expanding as in step $(II)$?