0
$\begingroup$

In the below link , it is mentioned that in case of Harvard Architecture it is impossible for the program memory to modify its contents so how can it happen since instructions are fetched from the Program Memory only , and there will be instructions to modify contents pertaining to that data only so how can it happen that the program cannot modify its own contents ?

http://spiroprojects.com/blog/cat-view-more.php?blogname=Difference-Between-Von-Neumann-Architecture-and-Harvard-Architecture&id=130

$\endgroup$
  • $\begingroup$ You answered it yourself. There are no instructions that can modify the memory containing the program. $\endgroup$ – gnasher729 Nov 9 '16 at 7:04
  • $\begingroup$ Sorry but I could not understand it clearly. $\endgroup$ – radhika Nov 9 '16 at 7:27

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.