I read in this assembly programming tutorial that 8 bits are used for data while 1 bit is for parity, which is then used for detecting parity error (caused by hardware fault or electrical disturbance).
Is this true?
A byte of data is eight bits, there may be more bits per byte of data that are used at the OS or even the hardware level for error checking (parity bit, or even a more advanced error detection scheme), but the data is eight bits and any parity bit is usually invisible to the software. A byte has been standardized to mean 'eight bits of data'. The text isn't wrong in saying there may be more bits dedicated to storing a byte of data of than the eight bits of data, but those aren't typically considered part of the byte per se, the text itself points to this fact.
You can see this in the following section of the tutorial:
Doubleword: a 4-byte (32 bit) data item
4*8=32, it might actually take up 36 bits on the system but for your intents and purposes it's only 32 bits.
Traditionally, a byte can be any size, and is just the smallest addressable unit of memory. These days, 8 bit bytes have pretty much been standardized for software. As JustAnotherSoul said, the hardware may store more bits than the 8 bits of data.
If you're working on programmable logic devices, like FPGAs, you might see that their internal memory is often addressable as 9-bit chunks, and as the HDL author, you could use that 9th bit for error checking or just to store larger amounts of data per "byte". When buying memory chips for custom hardware, you generally have the choice of 8 or 9 bit addressable units (or 16/18, 32/36, etc), and then it is up to you whether you have 9 bit "bytes" and what you do with that 9th bit if you choose to have it.
That text is extremely poorly worded. He is almost certainly talking about ECC (error-correcting code) RAM.
ECC ram will commonly store 8-bits worth of information using 9-bits. The extra bit-per-byte is used to store error correction codes.
(In both cases, every byte is spread across every chip. Image courtesy of Puget Systems)
This is all completely invisible to users of the hardware. In both cases, software using this RAM sees 8 bits per byte.
As an aside: error-correcting codes in RAM typically aren't actually 1 bit per byte; they're instead 8 bits per 8 bytes. This has the same space overhead, but has some additional advantages. See SECDED for more info.
Generally speaking, the short answer is that a byte is 8 bits. This oversimplifies the matter (sometimes even to the point of inaccuracy), but is the definition most people (including a large number of programmers) are familiar with, and the definition nearly everyone defaults to (regardless of how many differently-sized bytes they've had to work with).
More specifically, a byte is the smallest addressable memory unit for the given architecture, and is generally large enough to hold a single text character. On most modern architectures, a byte is defined as 8 bits; ISO/IEC 80000-13 also specifies that a byte is 8 bits, as does popular consensus (meaning that if you're talking about, say, 9-bit bytes, you're going to run into a lot of trouble unless you explicitly state that you don't mean normal bytes).
However, there are exceptions to this rule. For example:
sizeof(char), while also indirectly stating that a
charmust be a minimum of 8 bits, each byte must have a unique address, and there mustn't be any spaces between contiguous bytes in memory. This is to make the languages more portable than they would be if they explicitly required 8-bit bytes. [The number of bits in a byte is specified as
CHAR_BIT, in C library header "limits" (
So, in most cases, a byte will generally be 8 bits. If not, it's probably 9 bits, and may or may not be part of a 36-bit word.
Note that the term byte is not well-defined without context. As far as computer architectures are concerned, you can assume that a byte is 8-bit, at least for modern architectures. This was largely standardised by programming languages such as C, which required bytes to have at least 8 bits but didn't provide any guarantees for larger bytes, making 8 bits per byte the only safe assumption.
There are computers with addressable units larger than 8 bits (usually 16 or 32), but those units are usually called machine words, not bytes. For example, a DSP with 32K 32-bit RAM words would be advertised as having 128 KB or RAM, not 32 KB.
Things are not so well-defined when it comes to communication standards. ASCII is still widely used, and it has 7-bit bytes (which nicely fit in 8-bit bytes on computers). UART transceivers are still produced to have configurable byte size (usually, you get to pick at least between 6, 7 and 8 bits per byte, but 5 and 9 are not unheard of).
A byte is usually defined as the smallest individually addressable unit of memory space. It can be any size. There have been architectures with byte sizes anywhere between 6 and 9 bits, maybe even bigger. There are also architectures where the only addressable unit is the size of the bus, on such architectures we can either say that they simply have no byte, or the byte is the same size as the word (in one particular case I know of that would be 32 bit); either way, it is definitely not 8 bit. Likewise, there are bit-addressable architectures, on those architectures, we could again argue that bytes simply don't exist, or we could argue that bytes are 1 bit; either way is a sensible definition, but 8 bit is definitely wrong.
On many mainstream general purpose architectures, one byte contains 8 bit. However, that is not guaranteed. The further away you stray from the mainstream and/or from general purpose CPUs, the more likely you will encounter non-8-bit-bytes. This goes so far that some highly-portable software even makes the size configurable. E.g. older versions of GCC contained a macro called
BITS_PER_BYTE (or something like that), which configured the size of a byte for a particular architecture. I believe some older versions of NetBSD could be made to run on non-8-bit-per-byte architectures.
If you really want to stress that you are talking about an exact amount of 8 bit rather than the smallest addressable amount of memory, however large that may be, you can use the term octet, which is for example used in many newer RfCs.
When I started programming in 1960, we had 48 bit words with 6 bit bytes - they ware not called that name then, they were called characters. Then I worked on the Golem computer with 75 bit words and 15 bit bytes. Later, 6 bit bytes were the norm, until IBM came out with the 360, and nowadays a byte is commonly equivalent to an octet, i.e. 8 bits of data. Some hardware had additional bits for error detection and possibly for error correction, but these were not accessible by the software.
A byte is 8 bits.
In the distant past, there were different definitions of a memory word and of a byte. The suggestion that this ambiguity is widespread or is prevalent in today's life is false.
Since at least the late 1970's, a byte has been 8 bits. The mass populace of home computers and PCs have all unambiguously used a byte as an 8-bit value in their documentation, as have all of the data sheets and documentation for floppy disk drives, hard disk drives and PROM/EPROM/EEPROM/Flash EPROM/SRAM/SDRAM memory chips that I have read in that time period. (And I have personally read a great deal of them right across that time period.) Ethernet and a couple of other communications protocols stand out to me as unusual in talking about octets.
The ambiguity of the term byte is itself a rare and obscure thing. Very, very few of the population of programmers, design engineers, test engineers, salespeople, service engineers or average punters in the last 30 years or more would think it meant something other than an 8-bit value, if they recognised the word at all.
When a byte is handled by hardware, such as when stored in memory chips or communicated along wire, the hardware may add redundant data to the byte. This may later assist in detecting hardware errors so that unreliable data can be recognised and discarded (e.g. parity, checksum, CRC). Or it may allow errors in the data to be corrected and the data recovered (e.g. ECC). Either way, the redundant data will be discarded when the byte has been retrieved or received for further processing. The byte remains the central 8-bit value and the redundant data remains redundant data.
First, the tutorial that you are referencing seems to be quite outdated, and seems to be directed at outdated versions of x86 processors, without stating it, so lots of the things you read there will not be understood by others (for example if you claim that a WORD is 2 bytes, people will either not know what you are talking about, or they will know that you have been taught based on very outdated x86 processors and will know what to expect).
A byte is whatever number of bits someone decides it should be. It could be 8 bit, or 9 bit, or 16 bit, anything. In 2016, in most cases a byte will be eight bit. To be safe you can use the term octet - an octet is always, always, eight bits.
The real confusion here is confusing two questions: 1. What is the number of bits in a byte? 2. If I wanted to transfer one byte from one place to another, or if I wanted to store a byte, using practical physical means, how would I do that? The second question is usually of little interest to you, unless you work at a company making modems, or hard drives, or SSD drives. In practice you are interested in the first question, and for the second one you just say "well, someone looks after that".
The parity bit that was mentioned is a primitive mechanism that helps detecting that when a byte is stored in memory, and later the byte is read, the memory has changed by some accident. It's not very good at that, because it won't find that two bits have been changed so a change is likely to go undetected, and it cannot recover from the problem because there is no way to find out which of the 8 bits have changed, or even if the parity bit has changed.
Parity bits are practically not used in that primitive form. Data that is stored permanently is usually protected in more complicated ways, for example by adding a 32 bit or longer checksum to a block of 1024 bytes - which takes much less extra space (0.4% in this example instead of 12.5%) and is much less likely to not find out when something is wrong.
Despite the really excellent answers given here, I'm surprised that no one has pointed that parity bits or error correction bits are by definition 'metadata' and so not part of the byte itself.
A byte has 8 bits!
In modern usage, a byte is 8 bits, period (although it has historically had other definitions). On the other hand, a data word is whatever the hardware in question handles as an atomic unit - could be 8 bits, 9 bits, 10 bits, 12 bits, 16 bits, 20 bits, 24 bits, 32 bits, etc. Various computer systems over the years have had all sorts of different word sizes.
To implement a memory system or a transmission protocol, it is beneficial to add error detection/correction which involves additional bits. They don't make for a 9-bit byte because, as stated above, a byte is 8 bits.
Various schemes add error detection and/or correction in various ways.
The typical use of parity is to add an extra bit to the transmission word so that the receiver can detect a single bit of error.
A scheme which can provide single-bit error correction involves the addition of 4 ECC bits per 32 bit data word. This just happens to be arithmetically equivalent to 1 bit per byte, but it cannot/does not work that way. One 36-bit data word can carry enough information to recover from a single bit error for a 32-bit data space.
8 bits. Inside the cpu and keyboard, it is 9 and 11 bit. User data is represented in 8 bits though. Keys on keyboard send sings which is devided into 11 bits. 1 starting bit, 1 ending bit, 1 parity bit and 8 bits representing a key pressed.