I am unsure I expressed myself correctly.
Anyway, I want to figure out what is the initial state of an automata who had its epsilon transitions removed and who was determinised.
In my text book it is stated, that suppose A is NFA with $\epsilon$-moves, suppose $q_0$ its initial state. Then the initial state of the equivalent DFA is the E-closure of $q_0$.
Yet in one of the softwares recommended by one of my teachers, $\epsilon$-NFA to DFA algorithm always puts the initial state as $q_0$ and not E-closure($q_0$).