What is the period of N xored identical random number generators, with differing seeds?

This question is a kinda spin off from Why do we not combine random number generators?

If for example we had N identical type random number generators, with N different seeds, what would the period be if their outputs were xored together? Would it be period, N x period or period (power N)?

So a numerical example would be:

2 linear feedback shift registers of 10 bits.

1 LFSR's period = 1023.

2 xored LFSRs' period = 1023, 2046 or 1046529?

(I have a sense that it's period but I can't overcome that fact that the state size is so much bigger.)

• The period is hardly worth worrying about in practice; it's not the hard part. It's super-easy to build generators with a large period. What's harder is to build a generator that produces high-quality random output (i.e., where the outputs can't be predicted from previous outputs). So, the answer to your question probably won't be of much help in understanding whether it's useful to xor generators or not. – D.W. Jan 13 '17 at 1:30
• The link to the prior question is broken. Would you like to fix that? – D.W. Jan 13 '17 at 1:31

I will assume the N random generators have independent seeds and states. Suppose their periods are $t_1,\dots,t_N$. Then the period of their xor is a divisor of $\operatorname{lcm}(t_1,\dots,t_N)$. Typically, it will be exactly $\operatorname{lcm}(t_1,\dots,t_N)$, but I don't know whether that is guaranteed in all cases.
If all $N$ generators have the same period $t$, then the period of their xor is a divisor of $t$ (and thus cannot be any larger than $t$).
• Shouldn't it be the LCM? For example, the XOR of $(01)^\omega$ and $(001)^\omega$ is $(011100)^\omega$. – Yuval Filmus Mar 14 '17 at 3:20