# NFA to DFA accepting states

I was working through an NFA to DFA conversion tutorial: where I'm converting the following NFA to a DFA:

I used lazy subset construction which I'm sure the tutorial did as well because we had the same transition table of:

delta      |  0        |  1       |
===========+===========+==========+
{a}        |{a,b,c,d,e}|{d,e}
{a,b,c,d,e}|{a,b,c,d,e}|{b,d,e}
{d,e}      |{e}        |{∅}
{b,d,e}    |{c,e}      |{e}
{e}        |{∅}        |{∅}
{c,e}      |{∅}        |{b}
{b}        |{c}        |{e}
{c}        |{∅}        |{b}


However, there state diagram for the resulting DFA is this:

I'm confused as to why the set {b,d,e} isn't being labeled as an accepting state.

Also, I don't know if I'm allowed to ask this but if there is a place with more NFA to DFA converting practice I'd love to know, right now I'm just using any old study guide I can find on google.