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I need to describe by a graph a turing machine that can accept the language:
A = {0^(3^n ) |n≥0} = { 0 , 000 , 0^9 , 0^27 , ... }. zeros in powers of 3

This here is a turing machine that can accept the language:
A = {0^(2^n ) |n≥0} If that helps somehow.. enter image description here

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  • $\begingroup$ Mmm.. I tried a lot of things, never got it right :/ I expect a drawing like the one for the power of 2's that I attached $\endgroup$ – Davis8988 Mar 27 '17 at 7:58
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I wanted to post this as a tip cause this catches pow 3 but also (pow 3)*2 :: 9 and 18 I sadly can't solve it perfectly right now but I'm certain you don't need more than 9 states, hope it helps you solve and I'm interested to see a real solution

Ps for you just a --> 0 Not Solution

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  • $\begingroup$ Could you add textual description to your diagram? How does it work? Why does it work? If it does not, it shouldn't be posted as the answer. $\endgroup$ – Evil Apr 8 '17 at 13:53
  • $\begingroup$ As I said I wanted to post this as a comment but I can't. I could only post a solution. As to how it works: well i tried to force it to do a circle of three twice so it would be a 3^n, maybe if ill force it to do 3 circles it will be perfect? I'm sorry to say I can't explain better than that $\endgroup$ – Flamerion Apr 9 '17 at 19:40
  • $\begingroup$ I will hopefully have a full solution in a week or two as me and some friends are working on it $\endgroup$ – Flamerion Apr 9 '17 at 19:48

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