Rice-Shapiro theorem is:
Let $Γ$ be a set of computable functions such that the set $R_Γ$ is recursively enumerable. We have $f ∈ Γ$ if and only if there exists a finite function $θ ∈ Γ$ such that $θ ⊆ f$.
If $Γ$ is singleton set, for example $Γ = \lbrace ϕ_{10}\rbrace$ then $R_Γ = \lbrace 10 \rbrace$ and is recursively enumerable, but $Γ$ does not satisfy:
$f ∈ Γ$ if and only if there exists a finite function $θ ∈ Γ$ such that $θ ⊆ f$.
Where I have made a mistake?