# Prove or disprove the given equivalence [duplicate]

f(n) = n/100 = Ω(n) . I am new at proving asymptotic notations , especially at big-Ω. That's why I even didnt start the beginning myself. I tried to prove myself as looking at other proofs and searched on the internet to find same question but I couldnt find. I dont think so this question is a duplicate of another which was asked here. Thanks for helps.

## marked as duplicate by Raphael♦ algorithms StackExchange.ready(function() { if (StackExchange.options.isMobile) return; $('.dupe-hammer-message-hover:not(.hover-bound)').each(function() { var$hover = $(this).addClass('hover-bound'),$msg = $hover.siblings('.dupe-hammer-message');$hover.hover( function() { $hover.showInfoMessage('', { messageElement:$msg.clone().show(), transient: false, position: { my: 'bottom left', at: 'top center', offsetTop: -7 }, dismissable: false, relativeToBody: true }); }, function() { StackExchange.helpers.removeMessages(); } ); }); }); Oct 14 '17 at 19:17

• Could you please post what you tried to solve it yourself? Where did you get stuck? – fade2black Oct 14 '17 at 18:35

I assume $n$ takes only positive values. By the definition of Big-Omega you could prove it by showing the following

$$\lim_{n \rightarrow \infty}\frac{\frac{n}{100}}{n} >0$$

The rest is a simple exercise.