Nodes A and B are accessing a shared medium using CSMA/CD, with a propagation delay of 245-bit times between them (i.e., propagation delay equals the amount of time to transmit 245 bits). The minimum frame size is 64 bytes. Suppose node 𝐵 begins transmitting a frame at 𝑡 = 0 bit time. Before A finishes, node B begins transmitting a frame. Assume no other nodes are active.
What is the latest time by which B can begin its transmission?
Attempt: Considering that t=512 bit times is the time at which A finishes transmission, shouldn't the latest time by which B begins its transmission be at t=245 bit time? (At t=1, 1st bit is pushed on the link, and at t=245 bit time, this is the last "timing" that B can start transmitting before it senses that A is transmitting). However, the answer given is 244-bit time and I do not understand why.