Question: Given: Class B IP address 22.214.171.124.
Network when divided into 4 sub networks, each one requires 16,000 IP addresses. They need to be assigned sequentially without gaps.
Find the sub networks.
Here is my solution:
Total IP addresses in 1 subnet are 16000 = 2^14 – 384 Bits required for subnet: 4 = 2^2 = 2 bits
Bits Required for Host id: 16000 = 214 =14 bits
Subnet mask: 255.255.192.0
Subnet 1: 126.96.36.199 To 188.8.131.52 = (62x256) +128=16000
Subnet 2: 184.108.40.206 To 220.127.116.11
Subnet 3: 18.104.22.168 To 22.214.171.124
However in the solution booklet something else was mentioned( solution given below) which confused me. Please help/guide me.
What do them mean by wasting few IP addresses and how are those particular ones selected. Moreover how did we get the solution given in the image below.