0
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A 010101
B 110011
C 111000
D 000111

The minimum Hamming distance of those code words is 3 as the minimum difference is 3 but the correct answer is 2.

How can I find the correct Hamming distance?

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1
$\begingroup$
  • A 010101
  • D 000111

There are two bits different (namely the bold ones). So the hamming distance is 2.

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