I am simplifying a big formula to find the big notation of a certain algorithm. The expression is:
$$\log_2(1-l)/\log_2(1-2^{nH(m/n)-n})$$
where $0.98<l< 1$, $0<m<n/2$, $n>0$ and $H$ is the binary entropy function.
In practice, I known that the algorithm is exponential, but I do not known how simplify that to get the exponential expression. Could you help me please?