Let L1 = L2 union L3 find values such that L1 is context free and L2 and L3 are not.
So far I have: L1 = $a^nb^n$ L2 = $a^*b^*$ L3 = $a^+b^+$
Is this acceptable?? Since L2 covers everything including epsilon and L3 is the same but does not include epsilon?
I know L2 is regular so I guess that is also not a CFL. Another problem is that the a's and b's aren't linked in L2 and L3, so either one can always have more a's than b's and vice versa.