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Consider such question:

(Prove or disprove) There exists a language in $TIME(2^{n^2})$ that is not in $NTIME(n)$.

I guess that answer is yes because $TIME(2^{n^2})$ and $NTIME(n)$ are totally different classes ($TIME(2^{n})$ and $NTIME(n)$ are the same classes, i guess). How to prove it strictly? (Or my guess is incorrect?)

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    $\begingroup$ Use $NTIME(n) \subseteq TIME(2^{O(n)})$ together with the deterministic time hierarchy theorem. $\endgroup$ – Yuval Filmus Jun 16 '18 at 18:04
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Combine the following two facts:

  • $\mathsf{NTIME}(n) \subseteq \mathsf{TIME}(2^{O(n)})$, by deterministic simulation of nondeterminism.
  • $\mathsf{TIME}(2^{O(n)}) \subsetneq \mathsf{TIME}(2^{n^2})$, by the time hierarchy theorem.
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