# QTM & Halting problem [duplicate]

"Can QTM (Quantum Turing machine) solve halting problem" Why not have an immediate answer "No QTM Can't do this", we know that Turing proved it impossible when DTM , i meant , " Why we cant use the same proof which turing use it" Let H be a program in a quantum turing machine that will solve the issue of halting , why not say that a contradiction will occur Thanks

## marked as duplicate by David Richerby, Evil, Yuval Filmus turing-machines StackExchange.ready(function() { if (StackExchange.options.isMobile) return; $('.dupe-hammer-message-hover:not(.hover-bound)').each(function() { var$hover = $(this).addClass('hover-bound'),$msg = $hover.siblings('.dupe-hammer-message');$hover.hover( function() { $hover.showInfoMessage('', { messageElement:$msg.clone().show(), transient: false, position: { my: 'bottom left', at: 'top center', offsetTop: -7 }, dismissable: false, relativeToBody: true }); }, function() { StackExchange.helpers.removeMessages(); } ); }); }); Aug 23 '18 at 14:43

Because we can simulate QTM with DTM and it is an easier proof method than proving directly for QTM (which we can do). Also, this method of simulating a model with DTM to prove they are equivalent in power is somewhat a standard tool, not just for various TMs, but also for other computaitonal models ($\lambda$-calculus, RAM-machines,$\ldots$)