# QTM & Halting problem [duplicate]

"Can QTM (Quantum Turing machine) solve halting problem" Why not have an immediate answer "No QTM Can't do this", we know that Turing proved it impossible when DTM , i meant , " Why we cant use the same proof which turing use it" Let H be a program in a quantum turing machine that will solve the issue of halting , why not say that a contradiction will occur Thanks

Because we can simulate QTM with DTM and it is an easier proof method than proving directly for QTM (which we can do). Also, this method of simulating a model with DTM to prove they are equivalent in power is somewhat a standard tool, not just for various TMs, but also for other computaitonal models ($\lambda$-calculus, RAM-machines,$\ldots$)