4
$\begingroup$

The paper "CPS Translating Inductive and Coinductive Types" mentions that there is an isomorphism between inductive (mu) and coinductive (nu) types, which they use for their translation. It states that:

$$\neg\mu Z.A(\neg Z)\ \cong\ \nu Z.\neg A(Z)$$

...but it gives no more details about it. Is this isomorphism correct? Is it constructive? Where could I find more information about it?

I've spent several hours trying to prove (any side of) it on Coq, using the standard impredicative encodings for those (e.g., see here), but failed.

$\endgroup$

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Browse other questions tagged or ask your own question.