How to find $L_q = \emptyset$, a state that is not reachable for any given string?

In the book Introduction to Languages and the Theory of Computation, I'm reading section 2.6 on how to minimize the number of states in an FA.

I'm having trouble understanding a notation defined as $L_q$. Here's what the book says:

Suppose we have a finite automaton $M = (Q, \Sigma, q_0, A, \delta)$ accepting $L \subseteq \Sigma^*$. For a state $q$ of $M$, we have introduced the notation $L_q$ to denote the set of strings that cause $M$ to be in state $q$:

$$L_q = \{ x \in \Sigma^* | \delta^*(q_0, x) = q\}$$.

The first step in reducing the number of states of M as much as possible is to eliminate every state $q$ for which $L_q$ = $\emptyset$, along with transitions from these states. None of these states is reachable from the initial state, and eliminating them does not change the language accepted by $M$.

I tried looking at this automaton to try to understand this definition: How can any of the states $1$ through $5$ be $L_q = \emptyset$ if I can find a string that can reach every state for this FA?

That is I can reach state $2$ with string $a$, and state $5$ with string $ab$, etc. Is this a correct way to approach this?

You're right. There is no such state with $L_q = \emptyset$
one more thing you can add is that , a state having $$L = \emptyset$$ cannot be reached from start state with any transition. hence if a state exists without being reached by start state then the language associated with that state is $$\emptyset$$ . further during dfa unless not specified for minimization such state does not exists